{ "numMessagesInTopic": 12, "nextInTime": 1952, "senderId": "BxI2qbtgssJ1MHZxZ9BZnSFu_H2SuAB8rv4Kh0cvWKg6fxLGMzGgF-y6efobaHBEM3qv-dnpIGdusYNSWW7x4cvS9IA", "systemMessage": false, "subject": "100 hz tone....OT delete if need be.", "from": ""Carol" <frankwa@...>", "authorName": "Carol", "msgSnippet": "... Tom ... To see how long it takes for a freq or period of a wave divide 1000 by the freq. 1000 divided by 100hz equals 10 ms. So knowing that You can see", "msgId": 1951, "profile": "petpeavey", "topicId": 1941, "spamInfo": { "reason": "0", "isSpam": false }, "replyTo": "LIST", "userId": 8787581, "messageBody": "
>Tom
\n> Guess where it sounded best? Well, that was a little weird. It
\n> sounded good at 4.2ms, 14.4ms and 24.2ms. I assume there was some
\n> sort of time based pahse thing going on here. So, you have to know
\n> at least a ballpark figure in order to set it by ear.
\n>
\n> I will use this method if I go through the ADA8000. That may
\n> introduce some more latency that I need to account for.
\n>
\n> Many thanks,
\n>
\n> TOm
\n
\n
\n
>To see how long it takes for a freq or period of a wave divide 1000
\n